CALCULATION OF BASIC MECHANICS WITH LOADS ON BEAMS evenly SIMPLE

CALCULATION OF BASIC MECHANICS WITH LOADS ON BEAMS evenly SIMPLE

okay this time I will discuss one example of a distributed load on a beam calculation simple in pehitungan basic engineering mechanics.

Reinforced concrete beams measuring 300 mm x 500 mm is located at the top of the simple supported as shown in the image above .In the work load on the beam die plate (q_dpelat) = 2 kN / m 'and the burden of life (QL) = 2 kN / m'. If the weight of the concrete is calculated at 25 kN / m3, calculate the necessary torque and nominal moments for planning the block!

Completion !!

(A) Calculate the necessary torque beam (beam Mu)

Heavy beams = 0.3 x 0.5 x 25 = 3.75 kN / m '

Dead load:

The dead load = weight of the beam, (q_Dbalok) + Weight plate (q_Dpelat)

= 3.75 kN / m '+ 2.00 kN / m'

= 5.75 kN / m '

Moments due to dead load

MD (Moment Dead) = 1/8 * QD * L2 = 1/8 * 5.75 * 82 = 46 kn- m

Moment due to live load

ML (Moment of Life) = QL * 1/8 * 1/8 * L2 = 2 * 82 = 16 kn- m

Moment need beam (Mu)

MD mu = 1.2 + 1.6 ML

= 1.2 (46) + 1.6 (16)

= 80.8 kN-m

Mu calculate it another way:

Expenses need (qu) = 1.2 * QD + 1.6 * QL

= 1.2 * 5.75 + 1.6 * 2

= 10.1 kN / m '

The moment of need (Mu) = 1/8 * qu * L2

= 1/8 * qu * L2

= 80.8 kN-m

(B) Calculate the nominal torque Mn beam

in Learning about the beams and reinforced concrete slab (for beginners) already explained that a strong plan at least equal to a strong need to beam. Strong need has been calculated that Mu of 80.8 kN-m

Strong value plan = reduction factor kekutan * nominal compressive strength

So, the moment the plan (Mr) = the reduction factor kekutan * nominal moment (Mn)

According to the equation is obtained: Mr> or = Mu

If taken Mr = Mu = 80.8 KNM and power reduction factor for the (structure resist bending) = 0.80, the obtained

Mn = Mr / power reduction factor

= 80.8 / 0.8

= 101 KNM

Thus, Mn = 101 KNM

thanks for your atention and succesfull for you